x^2+x+4=1

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Solution for x^2+x+4=1 equation: 



x^2+x+4=1

We move all terms to the left:

x^2+x+4-(1)=0

We add all the numbers together, and all the variables

x^2+x+3=0

a = 1; b = 1; c = +3;
Δ = b2-4ac
Δ = 12-4·1·3
Δ = -11
Delta is less than zero, so there is no solution for the equation

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